which one have largest bond Angle and why ?
a ) OF2
b ) OCl2
explain with suitable reason !!
thanks and the best
Answers
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hey here is your answer
0F2 and ocl2 have 2 BP and 2 LP. it is expected that the bond angle of this molecule should not be ideal and should debite form 109. 5°. the observe result can be explained in terms of π back bonding that is 2 p π and 3D π .this type of bonding occurs in ocl2 because of this presence of the vacant 3D orbital in CL. this is existence of π back bonding increase the cl -o -cl bonding in due to the enhanced BP BP repulsion it may also be noted that due to the engagement of the oxygen lone pair in π back bonding LP LP repulsion also decreases, indirectly help the opening up of the bond angle. In of2 the bond angle will be guided only by the electronegativity rule.
hope you understand
0F2 and ocl2 have 2 BP and 2 LP. it is expected that the bond angle of this molecule should not be ideal and should debite form 109. 5°. the observe result can be explained in terms of π back bonding that is 2 p π and 3D π .this type of bonding occurs in ocl2 because of this presence of the vacant 3D orbital in CL. this is existence of π back bonding increase the cl -o -cl bonding in due to the enhanced BP BP repulsion it may also be noted that due to the engagement of the oxygen lone pair in π back bonding LP LP repulsion also decreases, indirectly help the opening up of the bond angle. In of2 the bond angle will be guided only by the electronegativity rule.
hope you understand
Answered by
1
0F2 and ocl2 have 2 BP and 2 LP. it is expected that the bond angle of this molecule should not be ideal and should debite form 109. 5°. the observe result can be explained in terms of π back bonding that is 2 p π and 3D π .this type of bonding occurs in ocl2 because of this presence of the vacant 3D orbital in CL. this is existence of π back bonding increase the cl -o -cl bonding in due to the enhanced BP BP repulsion it may also be noted that due to the engagement of the oxygen lone pair in π back bonding LP LP repulsion also decreases, indirectly help the opening up of the bond angle. In of2 the bond angle will be guided only by the electronegativity rule.
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