Chemistry, asked by ankita810, 8 months ago

which one is correct please give explanation​

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Answered by TrickYwriTer
3

Explanation:

Option 1 :-

2g of Butane (C4H10)

As we know that :-

  • mass = n × GMM

Molar mass of C4H10 -

» 12×4 + 1×10

» 48 + 10

  • » 58 g/mol

Then,

  • n = mass/GMM

» 2/58

  • » 1/29 mole

And

  • Number of molecules = n × Na
  • here we took Na = 6 × 10²³ (approx value)

» 1/29 × 6 × 10²³

  • » 6/29 × 10²³

Option 2 :-

2g of N2

Molar mass of N2 -

» 14×2

  • » 28 g/mol

Then,

  • n = mass/GAM

» 2/28

  • » 1/14 mole

And

  • Number of molecules = n × Na

» 1/14 × 6 × 10²³

  • » 3/7 × 10²³

Option 3 :-

2g of Ag

Molar mass of Ag = 108 g/mol

Then,

n = 2/108

  • » 1/54 mole

And

  • Number of molecules = n × Na

» 1/54 × 6 × 10²³

  • » 1/9 × 10²³

Option 4 :-

2g of H2O

Molar mass of H2O -

» 1×2 + 16

  • » 18 g/mol

Then,

n = 2/18

  • » 1/9 mole

And

  • Number of molecules = n × Na

» 1/9 × 6 × 10²³

  • » 2/3 × 10²³

Hence,

2g of H2O has highest number of atoms.

Answered by HeartHacker
1

Answer:

option A

2gof butane C4H10

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