Question

which one is correct.

y= ABC+B'C'+A'B' INTO CANONICAL FORM IS

(1) y= Σm(0,1,4)

(2) y= Σm(0,1,7)

(3) y= Σm(1,4,7)

(4) y= Σm(0,1,4,7)

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Answer 1

Answer:

(4)

Explanation:

ABC + B'C' + A'B'

ABC + AB'C' + A'B'C' + A'B'C + A'B'C'

ABC + AB'C' + A'B'C' + A'B'C

In SOP We took 1 so

111 + 100 + 000 + 001

7 , 4, 0, 1

so, y= Σm(0,1,4,7)

Answer 2

Given:

y = ABC + B'C' + A'B'

To Find:

the correct option

Solution:

Now,

ABC + B'C' + A'B'

ABC + AB'C' + A'B'C' + A'B'C'

Then,

111 + 100 + 000 + 001

7, 4, 0, 1

So, y = ∑m(0,1,4,7)

Therefore, the correct option is(4).