Question

which one is the integating factor the differential equation xy'+xy=1​

Answer 1

Answer:

$\\ (1−x2)dxdy−xy \\ \: = \: 1</p><p></p><p> \\ ⇒dxdy+1−x2−xy=1−x21</p><p></p><p> \\ Here, P(x)=−1−x2x and \\  Q(x)=1−x21</p><p> \\ </p><p>Then,  \\ </p><p></p><p>I.F=e∫P(x)dx=e21∫1−x2−2xdx \: = \: e21log(−x2+1)=−x2+1</p><p> \\ </p><p> \: \\ =1−x2</p><p>$