Which one is the odd one out:8, 27, 16, 64?
Sam01124:
27 will be the answer as all the rest are divisible by 8. Also others are even numbers but 27 is odd number.
Answers
Answered by
5
The odd one out is 16, all others are cube numbers.
Answered by
6
Hello!
Here is your answer!
_________________
There can be Two answer!
1. 27 is odd
Reason = All the other numbers are even number ( 8 , 16 , 64 ) While 27 is an odd number and moreover rest all r divisible by 8 but 27 is not divisible by 8
2. 16 is odd
Reason = All other numbers are perfect cubes
Example
![\sqrt[3]{8} = 2 \times 2 \times 2 \sqrt[3]{8} = 2 \times 2 \times 2](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B8%7D+%3D+2+%5Ctimes+2+%5Ctimes+2+)
![\sqrt[3]{27} = 3 \times 3 \times 3 \sqrt[3]{27} = 3 \times 3 \times 3](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B27%7D+%3D+3+%5Ctimes+3+%5Ctimes+3)
![\sqrt[3]{64} = 4 \times 4 \times 4 \sqrt[3]{64} = 4 \times 4 \times 4](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B64%7D+%3D+4+%5Ctimes+4+%5Ctimes+4)
While
16 Is not a perfect cube of any number
Hope it helps you out!!√
Here is your answer!
_________________
There can be Two answer!
1. 27 is odd
Reason = All the other numbers are even number ( 8 , 16 , 64 ) While 27 is an odd number and moreover rest all r divisible by 8 but 27 is not divisible by 8
2. 16 is odd
Reason = All other numbers are perfect cubes
Example
While
16 Is not a perfect cube of any number
Hope it helps you out!!√
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