which one of the following give A+B =pi/4. a belongs to (0,pi/2) and b belong to (0,pi/2)
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The function `f(x) = {x+asqrt2 sinx, 0<=x<=pi/4 and 2x cotx+b, pi/4<=x<=pi/2 and a cos 2x-bsinx, pi/2,x<=pi` is continuous for `0<= x <=pi` ,then value ...
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Answer:
f:[0,4π]→[0,π],f(x)=cos
−1
(cosx)
⇒ point A, B, C satisfy f(x)=
10
10−x
Hence, 3 points
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