Question

Which one of the following has maximum number of atoms
a) 1 gram of mg
b) 1 gram of o2
c) 1 gram of li
d) 1 gram of ag​

Step by step method

Answer 1

Answer:

1 mol of any element = 6.022 x 10^23 atoms

a) 1 mol of Mg = 12 g = 6.022 x 10^23 atoms

1 g of Mg = (6.022/12) x 10^23 atoms

b) 1 mol of O2 = 2 mol of O = 32 g = 2*6.022 x 10^23 atoms

1 g of O2 = (2*6.022/32) x 10^23 atoms  

c) 1 mol of Li = 7 g = 6.022 x 10^23 atoms

1 g of Li = (6.022/7) x 10^23 atoms

d) 1 mol of Ag = 108 g = 6.022 x 10^23 atoms

1 g of Ag = (6.022/108) x 10^23 atoms

clearly more is the molar mass, more is denominator and less will be the number of atoms.

So, number of atoms are maximum in 1 g of Li and least in 1 g of Ag.