Question

which one of the following is a polynomial of degree 2
$\sqrt{x } + 6x + 7$
​

Answer 1

$\large \boxed{ \colorbox{pink}{༒ \underline{Given: } }}$

$\sqrt{x } + 6x + 7$ – (2x – 7) =0

$\sqrt{x } + 6x + 7$ (2x – 7)

${\huge{\underline{\small{\mathbb{\pink{Squaring \ both \ the \ Sides}}}}}}$

$\large \boxed{ \colorbox{Pink}{༒ \underline{Step by Step Solution } }}$

⇝$\sqrt{x } + 6x + 7$ = (2x – 7²)

or,

⇝$\sqrt{x } + 6x + 7$ = 4x² – 28x + 49

⇝$4x ² – 34x + 42 =0$ or,

⇝$2x – 17x +21 =0$ or,

⇝$2x – 14x – 3x + 21 =0$ or,

⇝$2x (x –7) –3 (x –7)$ or,

⇝$(x –7) (2x –3) =0$ or,

⇝$x =7$ or,

⇝x = $\frac{3}{2}$

Hence, Proved

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$\sf\red{Thank\:you!}$

$\sf\red{Be\:Brainly<3}$