Question

Which one of the following is equal to the pKa of a weak acid? 1.)Its relative molecular mass 2.)The pKb of its conjugate base 3.)The pH of a solution containing equal amounts of the acid and its conjugate base 4.)The equilibrium concentration of its conjugate base

Answer 1

Answer:

y

Explanation:

When an uncharged weak acid is added to water, a homogeneous equilibrium forms in which aqueous acid molecules, HA(aq), react with liquid water to form aqueous hydronium ions and aqueous anions, A-(aq). The latter are produced when the acid molecules lose H+ ions to water.

HA(aq) + H2O(l) H3O+(aq) + A-(aq)

In writing an equilibrium constant expression for this homogeneous equilibrium, we leave out the concentration of the liquid water. The equilibrium constant for this expression is called the acid dissociation constant, Ka.

= acid dissociation constant

When the equilibrium in question occurs in solution, the chemical formulas enclosed in brackets in the equilibrium constant expression represent the molarities of the substances (moles of solute per liter of solution).

Remember that H+ can be used to represent H3O+, thus simplifying our depiction of the reaction between a weak acid and water and its acid dissociation constant expression:

HA(aq) H+(aq) + A-(aq)

= acid dissociation constant

For example, acetic acid is a weak acid, because when it is added to water, it reacts with the water in a reversible fashion to form hydronium and acetate ions.

HC2H3O2(aq) + H2O(l) H3O+(aq) + C2H3O2-(aq)

or HC2H3O2(aq) H+(aq) + C2H3O2-(aq)

= 1.8 × 10-5

EXAMPLE 1 - Writing an Acid Dissociation Constant: Write the equation for the reaction between the weak acid nitrous acid and water, and write the expression for its acid dissociation constant.

Solution:

HNO2(aq) + H2O(l) H3O+(aq) + NO2-(aq)

or HNO2(aq) H+(aq) + NO2-(aq)

The table below lists acid dissociation constants for some common weak acids. These Ka values can be used to describe the relative strength of the acids. A stronger acid will generate more hydronium ions in solution. A larger Ka indicates a greater ratio of ions (including hydronium ions) to uncharged acid. Therefore, a larger Ka indicates a stronger acid. For example, the larger Ka for chlorous acid (1.2 × 10-2) compared to acetic acid (1.8 × 10-5) tells us that chlorous acid is stronger than acetic acid.

Acid Dissociation Constants, Ka, for Common Weak Acids

Weak Acid

Equation

Ka

acetic acid

HC2H3O2 H+ + C2H3O2-

1.8 × 10-5

benzoic acid

C6H5CO2H

H+ + C6H5CO2-

6.4 × 10-5

chlorous acid

HClO2 H+ + ClO2-

1.2 × 10-2

formic acid

HCHO2 H+ + CHO2-

1.8 × 10-4

hydrocyanic acid

HCN H+ + CN-

6.2 × 10-10

hydrofluoric acid

HF H+ + F-

7.2 × 10-4

hypobromous acid

HOBr H+ + OBr-

2 × 10-9

hypochlorous acid

HOCl H+ + OCl-

3.5 × 10-8

hypoiodous acid

HOI H+ + OI-

2 × 10-11

lactic acid

CH3CH(OH)CO2H

H+ + CH3CH(OH)CO2-

1.38 × 10-4

nitrous acid

HNO2 H+ + NO2-

4.0 × 10-4

phenol

HOC6H5 H+ + OC6H5-

1.6 × 10-10

propionic acid

CH3CH2CO2H

H+ + CH3CH2CO2-

1.3 × 10-5

The following study sheet describes one procedure for calculating the pH of solutions of weak acids. If you take other chemistry courses, you will find that there are variations on this procedure for some weak acid solutions.

Study Sheet - Calculating pH for Weak Acid Solutions

Tip-off - You are given the concentration of a weak acid solution and asked to calculate its pH.

General Steps -

STEP 1 Write the equation for the ionization of the weak acid in water.

HA(aq) H+(aq) + A-(aq)

STEP 2 Write the Ka expression for the weak acid.

STEP 3 Describe each equilibrium concentration in terms of x.

x = [H+]equilibrium = [A-]equilibrium

[HA]equilibrium = [HA]initial - x

STEP 4 Assume that the initial concentration of weak acid is approximately equal to the equilibrium concentration. (Weak acids are rarely ionized to a large degree. We can most often assume that the initial concentration added, [HA]initial is much larger than x. Thus, the equilibrium concentration is approximately equal to the concentration added. You may learn how to deal with weak acid solutions for which this approximation is not appropriate in other chemistry courses.)

[HA]equilibrium = [HA]initial

STEP 5 Plug the concentrations described in terms of x into the Ka expression, and solve for x.