Question

which one of the following statements is true. for a simple harmonie oscillator?
(A) K.E is maximum when x is maximum
(C) P.E is minimum when x is maximum
(B) K.E is maximum when Y is minimum
(D) P.E is maximum when x is minimum​

Answer 1

Answer:

The P.E. of a particle executing SHM is given by, U=12mω2y2U=12mω2y2

U is maximum when y=a=y=a= amplitude of vibration i.e., the particle is passing from the extremen position and is minimum when y=0,y=0, i.e., the particle is passing from the mean position:

The K.E. of a particle executing SHM is given by K=12mω2(a2−y2)K=12mω2(a2-y2)

K is maximum when y=0y=0, i.e., the particle is passing from the mean position and K is minumum when y=ay=a i.e., the particle is passing from the extremen position.

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