Which one of the following transitions in a hydrogen atom will emit a photon of shortest wavelength?
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n=2 to n=1
i hope this will help you
i hope this will help you
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Helloo!!
Total energy of an electron in a H atom−13.6z²/n²ev−13.6z²/n²ev
z=atomic number (1 for hydrogen), n=orbit number
For n=1 in Hydrogen, total energy = −13.6ev
For n=2, it is −3.4ev
In 6 to 1 transition the energy difference is highest, so the frequency of photon emitted will also be highest, thus, its wavelength will be lowest.
hope it helps!!
Total energy of an electron in a H atom−13.6z²/n²ev−13.6z²/n²ev
z=atomic number (1 for hydrogen), n=orbit number
For n=1 in Hydrogen, total energy = −13.6ev
For n=2, it is −3.4ev
In 6 to 1 transition the energy difference is highest, so the frequency of photon emitted will also be highest, thus, its wavelength will be lowest.
hope it helps!!
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