Which one of the points 10-8i, 11+6i is closest to 1+i
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Answer:
Heya.....❤✌
Let the given points as A( 10-8i), B (11+6i)
& C(1+i).
To find which point is more closer, we have to find the distance between AC &BC.
Hence,
AC = √(1-10)^2 + (1+8)^2
=√162
BC = √(1-11)^2 +(1-6)^2
= √125
Here, √162> √125
So, the point B is closer to C.
Hope it’s helpful........ ☺
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