Question

Which one of these is formed on heating sodium ethoxide with propyl iodide?

[A] Ethyl propyl ether

[C] Phenone

[B] Pentan-5-one

[D] None of these​

Answer 1

$\large \dag$ Question :-

Which one of these is formed on heating sodium ethoxide with propyl iodide?

[A] Ethyl propyl ether

[C] Phenone

[B] Pentan-5-one

[D] None of these

$\large \dag$ Answer :-

$\small\red\dashrightarrow\underline{\underline{\sf  \green{The   \: Answer \:  is  \: Ethyl \: propyl \: ether} } }$

$\large \dag$ Step by step Explanation :-

$\large\blue \bigstar$$\red {\rm \: \: Reaction :-}$

$\rm C_2H_5ONa + C_3H_7I \longrightarrow C_2H_5-O-C_3H_7+NaI$

this reaction takes place in in presence of dry Ether and on heating.

• The reaction which take place here is Williamson Ether synthesis reaction.

• The reaction occurred is nucleophilic substitution second order reaction $\large \sf ( _{SN} {}^{ \small2})$

• In this reaction nucleophile is alkyl halide that is propyl iodide .

• Common name of $\small\sf C_2H_5-O-C_3H_7$ is Ethyl - Propyl ether

Hence,

Ethyl - Propyl ether is formed .

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{\text Option \: [ \text A] \: is \: Correct }}}}}$

Answer 2

Answer:

$\large \dag$ Question :-

Which one of these is formed on heating sodium ethoxide with propyl iodide.

1. Ethyl Propyl Ether .
2. Phenone.
3. Pentone- 5-one .
4. None of these.

$\large \dag$ Answer :-

$\sf\tt\large{\red {\underline {\underline{⚘\;Option \;(A) \;Ethyl \;propyl \;ether \;is \;the \;correct \;answer \;to \;the \;Question:}}}}$

$\large \dag$ Solutions :-

Hey mate ,

In the question given that What will formed after on heating sodium ethoxide with propyl iodide.

And in the question also given the clues which we can tell the answer easily .

Here we write the reaction as ,

C2H5ONa +C3H7I ---》C2H5-O-C3H7+NaI.

This reaction forms in the presence on heating process or at dry of Ether

And ,

This is found on SN2 mechanisms.

Which is also called as Nucleophillic substitution reaction.

The name that we get the product name is

[C2H5-O-C3H7+NaI] ----》ethyl propyl ether .

Hence,

• Option (A) is correct answer for your question.

$\large \dag$ Conclusion :-

• Here dont get confuse i post (I) not as 1 value in the reaction)

$\large \dag$ Hope it helps u mate .

$\large \dag$ Thank you .