which operation to be performed between x+2y=6 and 3x-y=1 to eliminate y
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Answer:
To eliminate y : (i) + 2×(ii)
Solution : x = 8/7 , y = 17/7
Solution:
The given pair of linear equations is :
x + 2y = 6 ------(i)
3x - y = 1 --------(ii)
Let's , solve this system of linear equations by elimination method.
Multiplying both sides of eq-(ii) with 2 , we get ;
=> 2(3x - y) = 2•1
=> 6x - 2y = 2 ----------(iii)
Now,
Adding eq-(i) and (iii) , we can eliminate y .
=> x + 2y + 6x - 2y = 6 + 2
=> 7x = 8
=> x = 8/7
Thus,
To eliminate y , we would do the operation :
(i) + 2×(ii).
Also,
Putting x = 8/7 in eq-(ii) , we get ;
=> 3x - y = 1
=> y = 3x - 1
=> y = 3•(8/7) - 1
=> y = 24/7 - 1
=> y = (24 - 7)/7
=> y = 17/7
Hence,
The solution of the system of given linear equations is : x = 8/7 , y = 17/7 .
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