Question

which option is correct?
​

Answer 1

Answer:

Given :- The logarithmic form of a^x = N is :-

A) a = logxN

B) x = logaN

C) N=logax

D) N=logxa

Solution :-

we know that,

\begin{gathered}\bf\: if\:{a}^{n}=x,\\\bf\: then\: ,\\\bf log_{a}(x) = n\end{gathered}

ifa

n

=x,

then,

log

a

(x)=n

therefore, we can conclude that,

\begin{gathered} \rightarrow \: {a}^{x} = n\\\rightarrow \boxed{\bf \: x = log_{a}(n) (b)(ans.)}\end{gathered}

→a

x

=n

→

x=log

a

(n)(b)(ans.)

Learn more :-

● \orange{\bold{Product\:Rule\:Law:}}ProductRuleLaw:

loga (MN) = loga M + loga N

● \pink{\bold{Quotient\:Rule\:Law:}}QuotientRuleLaw:

loga (M/N) = loga M - loga N

● \green{\bold{Power\:Rule\:Law:}}PowerRuleLaw:

IogaM^(n) = n Ioga M