Math, asked by abhi16637, 10 months ago

which option will be correct pls tell me me guys with explanation

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Answered by Anonymous

$\huge\bigstar\huge\mathcal{\underline{ \underline{AnsweR}}}\red\bigstar$

$\boxed{\boxed{\large\red{option(c) \rightarrow9}}}$

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A matrix is of order of 3×3

$A_{3×3} \:$

now given that ......

|A|=3

therefore...

now we know that for a matrix A of order n ..

$\implies A{}^{-1}=\frac{adj(A)}{|A|} \\now \: \: w e \: know \: that.... \\ \rightarrow A.A{}^{-1} = I \\ \rightarrow A. \frac{adj(A)}{|A|}= I \\ \rightarrow A.adj(A) = |A|.I \\ \rightarrow |A.adj(A) | = |A| {}^{n} \\ \rightarrow |A| |adj(A)| = |A| {}^{n} \\ \rightarrow |adj(A)| = \frac{|A| {}^{n}}{|A| } \\ \rightarrow |adj(A)| = |A| {}^{n - 1} \\ now \: given \: |A| = 3 \: and \: \: n = 3( \because \: order \: is \: 3) \\ \rightarrow |adj(A)| = 3 {}^{3 - 1} \\ \rightarrow |adj(A)| = 3 {}^{2} \\ \rightarrow |adj(A)| = 9$

$\large\mathfrak{...hope\: this \:helps\: you.....}$

#answerwithquality & #BAL

Answered by missNAV143957

SSA PUNJABIO

KI HAAL CHAL........

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which option will be correct pls tell me me guys with explanation