Question

Which ordered pairs are in the solution set of the system of linear inequalities? y > x + 2 y < 2x + 3 (2, 2), (3, 1), (4, 2) (2, 2), (3, –1), (4, 1) (2, 2), (1, –2), (0, 2) (2, 2), (1, 2), (2, 0)

Answer 1

sorry for don't knowing your question .

Answer 2

Answer:

None of the given points lie in the solution region.

Step-by-step explanation:

We are given the system of inequalities,

$y > x+2$ and $y < 2x+3$.

Thus, using the 'Zero test' i.e. substituting (0,0) in the inequalities, we have,

$y > x+2$ implies 0 > 2, which is false and $y < 2x+3$ implies 0 < 3, which is true.

Thus, the solution region of $y > x+2$ is away from the origin and $y < 2x+3$ is towards the origin.

Thus, after plotting, we get the following graph.

From the graph, we see that only the point (0,2) lies on the boundary of the solution region.

But, the boundary is not included in the solution region as we have strict inequalities.

Thus, we get,

None of the given points lie in the solution region.