Math, asked by troymartinez999, 1 year ago

Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)?

Answers

Answered by kvnmurty
4
P= (3, 4) Q = (-2, 2)
Slope: of PQ = (2-4)/(-2-3) = 2/5
Line parallel to PQ: let it be
y = m x + c
y = 2x /5 + c
Ordered pair of points:
(x , 2x/5 +c)
Where c is a constant.
For example (x , 2x/5 + 1)

RajneeshSingh: Can u pls explain this
Answered by amitnrw
1

Given :   a line parallel to the line that contains (3, 4) and (–2, 2)

options are  (–2, –5) and (–7, –3) (–1, 1) and (–6, –1) (0, 0) and (2, 5) (1, 0) and (6, 2) (3, 0) and (8, 2)

To find : Which ordered pairs could be  on line - select all applicable from options

Solution:

Slope of line having points  (3, 4) and (–2, 2)

= ( 2 - 4)/(-2 - 3)

= (-2)/(-5)

= 2/5

Slope of line parallel to this line will also have slope of  2/5

Lets check each pair for slope

(–2, –5) and (–7, –3)  

Slope = ( -3 -(-5))/(-7 - (-2)) =  2/(-5) = - 2/5  ≠ 2/5

Does not lie on parallel line

(–1, 1) and (–6, –1)

Slope = ( -1 - 1 )/(-6 - (-1)) = -2/(-5) = 2/5

lies on parallel line

(0, 0) and (2, 5)

Slope = 5/2    ≠ 2/5

Does not lie on parallel line

(1, 0) and (6, 2)

Slope   = 2/5

lies on parallel line

(3, 0) and (8, 2)

Slop e=  2/5

lies on parallel line

(–1, 1) and (–6, –1)  , (1, 0) and (6, 2)  & (3, 0) and (8, 2)

lies on line parallel to  line  that contains (3, 4) and (–2, 2)

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