Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply.
Answers
Given : a line parallel to the line that contains (3, 4) and (–2, 2) and options (–2, –5) and (–7, –3) (–1, 1) and (–6, –1) (0, 0) and (2, 5) (1, 0) and (6, 2) (3, 0) and (8, 2)
To find : Which ordered pairs could be on line
Solution:
Slope of line having points (3, 4) and (–2, 2)
= ( 2 - 4)/(-2 - 3)
= (-2)/(-5)
= 2/5
Slope of line parallel to this line will also have slope of 2/5
Lets check each pair for slope
(–2, –5) and (–7, –3)
Slope = ( -3 -(-5))/(-7 - (-2)) = 2/(-5) = - 2/5 ≠ 2/5
Does not lie on parallel line
(–1, 1) and (–6, –1)
Slope = ( -1 - 1 )/(-6 - (-1)) = -2/(-5) = 2/5
lies on parallel line
(0, 0) and (2, 5)
Slope = 5/2 ≠ 2/5
Does not lie on parallel line
(1, 0) and (6, 2)
Slope = 2/5
lies on parallel line
(3, 0) and (8, 2)
Slop e= 2/5
lies on parallel line
(–1, 1) and (–6, –1) , (1, 0) and (6, 2) & (3, 0) and (8, 2)
lies on line parallel to line that contains (3, 4) and (–2, 2)
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Answer:
B D and E are the answers 2020 edge