Which out of 4S & 4p has more energy?
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the 4s electrons are lost first during ionization. The electrons lost first will come from the highest energy level, furthest from the influence of the nucleus. So the 4s orbital must have a higher energy than the 3d orbitals.
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Energy is directly proportional to (n+l) value. For 4s,4p,3d the (n+l) value is 4+0=4,4+1=5,3+2=5 respectively. Thus 4s has the least energy. Thus in accordance to Aufbau's rule, given statement is false.
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