Question

which part of the graph show accelerated motion .calculate the acceleration​

Answer 1

Answer:

Hope it will help you

Explanation:

Given graph is a VELOCITY-TIME graph of an object.

In VT graph:

1. The slope of the line at a particular time gives the acceleration of the object at that time.

2. Area under the graph gives the displacement of the object.

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Coming to the questions:

1. Part AB is accelerated motion as the slope of the graph(which gives the acceleration) is positive.

acceleration = slope

So acceleration = 1 m/s^2

2.Part CD is retarded motion as the slope of the graph(which gives the acceleration) is negative.

So acceleration = -1 m/s^2

Thus retardation is 1 m/s^2

3.

distance of the body in first 4 seconds = area under graph from t=0 to t=4s

area under graph from t=0 to t=4s = area of ∆ABE = 1/2 × 4 × 4 = 8m

Thus distance of the body in first 4 seconds is 8m