which piont on y-axis is equidistant from(2,3),and(-4,1)
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Hey there,
Since the given point is on y axis so the point can be written as-
(0,a)
By distance formula
√4+(3-a)²=√16+(a-1)²
squaring both sides we get-
-4=4a
a=-1
Hence the required point is (0,-1)
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Since the given point is on y axis so the point can be written as-
(0,a)
By distance formula
√4+(3-a)²=√16+(a-1)²
squaring both sides we get-
-4=4a
a=-1
Hence the required point is (0,-1)
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
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