Question

Which point on x-axis has its distance from the points A(7, 6) and B(–3, 4) in the ratio 1 : 2.

Answer 1

Answer:

Given points  A(7,6) and B(-3,4)

Let the point be P(x,0) [we know that point on x-axis is (x,0)]

So, AP=PB and AP2=PB2  

⇒(x-7)2+(0-6)2=(x+3)2+(0-4)2

x2+49-14x + 36=x2+9+6x + 16

49-9+36-16=6x+14x

40+20=20x

60/20=x

⇒x=3

Hence, point on x-axis which is equidistant from the points A(7,6) and B(-3,4) is (3,0)