Which presidential candidate did Jefferson support in 1808
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The United States presidential election of 1808 was the sixth quadrennial presidential election, held from Friday, November 4, to Wednesday, December 7, 1808. The Democratic-Republican candidate James Madison defeated Federalist candidate Charles Cotesworth Pinckney decisively. Madison's victory made him the first individual to succeed a president of the same party.
United States presidential election, 1808← 1804November 4 – December 7, 18081812 →175 electoral votes of the Electoral College
89 electoral votes needed to winTurnout36.8%[1] 13.0 pp NomineeJames MadisonCharles C. PinckneyPartyDemocratic-RepublicanFederalistHome stateVirginiaSouth CarolinaRunning mateGeorge ClintonRufus KingElectoral vote12247States carried125Popular vote124,73262,431Percentage64.7%32.4%
Presidential election results map. Greendenotes states won by Madison, burnt orangedenotes states won by Pinckney, light greendenotes states won by Clinton. Numbers indicate the number of electoral votes allotted to each state.
President before election
Thomas Jefferson
Democratic-Republican
Elected President
James Madison
Democratic-Republican
Madison had served as Secretary of Statesince President Thomas Jefferson took office in 1801. Jefferson, who had declined to run for a third term, threw his strong support behind Madison, a fellow Virginian. Sitting Vice President George Clinton and former Ambassador James Monroe both challenged Madison for leadership of the party, but Madison won his party's nomination and Clinton was re-nominated as vice president. The Federalists chose to re-nominate Pinckney, a former ambassador who had served as the party's 1804 nominee.
Despite the unpopularity of the Embargo Act of 1807, Madison won the vast majority of electoral votes outside of the Federalist stronghold of New England. Clinton received six electoral votes for president from his home state of New York. This election was the first of two instances in American history in which a new president was selected but the incumbent vice president won re-election, the other being in 1828.
United States presidential election, 1808← 1804November 4 – December 7, 18081812 →175 electoral votes of the Electoral College
89 electoral votes needed to winTurnout36.8%[1] 13.0 pp NomineeJames MadisonCharles C. PinckneyPartyDemocratic-RepublicanFederalistHome stateVirginiaSouth CarolinaRunning mateGeorge ClintonRufus KingElectoral vote12247States carried125Popular vote124,73262,431Percentage64.7%32.4%
Presidential election results map. Greendenotes states won by Madison, burnt orangedenotes states won by Pinckney, light greendenotes states won by Clinton. Numbers indicate the number of electoral votes allotted to each state.
President before election
Thomas Jefferson
Democratic-Republican
Elected President
James Madison
Democratic-Republican
Madison had served as Secretary of Statesince President Thomas Jefferson took office in 1801. Jefferson, who had declined to run for a third term, threw his strong support behind Madison, a fellow Virginian. Sitting Vice President George Clinton and former Ambassador James Monroe both challenged Madison for leadership of the party, but Madison won his party's nomination and Clinton was re-nominated as vice president. The Federalists chose to re-nominate Pinckney, a former ambassador who had served as the party's 1804 nominee.
Despite the unpopularity of the Embargo Act of 1807, Madison won the vast majority of electoral votes outside of the Federalist stronghold of New England. Clinton received six electoral votes for president from his home state of New York. This election was the first of two instances in American history in which a new president was selected but the incumbent vice president won re-election, the other being in 1828.
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