Which product is obtained by reaction of ethyl cyanide with methyl magnesium bromide?
Answers
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✍✍Answer✍✍
✨✨CH3-CH2-CN + C6H5-MgBr = CH3-CH2-CO-C6H5 +NH3 + H2O.✨✨
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Answer:
Butanone (Methyl ethyl ketone)
Explanation:
Butanone, also known as methyl ethyl ketone, is obtained as a product of the reaction between ethyl cyanide and methyl magnesium bromide after hydrolysis.
The reaction is C₂H₅-CN + CH₃-MgBr = C₂H₅-CO-CH₃ +NH₃ + H₂O
Butanone is a colorless liquid with the smell of acetone mixed with mint. This reaction plays a very important role in most of the industries that are involved in the manufacturing of paraffin wax, plastics, and textiles. Methyl ethyl ketone is used as a solvent in the manufacturing of nitrocellulose coatings, gums, synthetic rubber, cellulose acetate, and resins. Butanone is also used as a flavoring agent, in paints, in glues, in the cleaning of surgical and electronic instruments, etc.
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