Question

which product is obtained.
when methyl cyanide the
reduced by sodium and ethanol??l​

Answer 1

Answer:

you give me all the chemicals then I tell you

Answer 2

Explanation:

The reaction below shows the reduction of CH3CH2CH2CH2CN with sodium in 86% butanol. ... Na/C2H5OH is a reducing agent and called as Mendius reagent. CH3CN when reacts with mendius reagent it will form acetic acid and ammonia.