Question

which products are obtained on passing carbon dioxide in less proportion and Inverse proportion in solution of calcium hydroxide state the solubility of products in water​

Answer 1

Products which are obtained on passing carbon dioxide in less proportion and Inverse proportion in solution of calcium hydroxide state the solubility of products in water​:

$CO_2 + Ca(OH)_2 = CaCO_3 + H_2O$ (precipitate).

When you pass carbon dioxide through a solution of calcium hydroxide in small quantities, the reaction mixture that is formed is called lime water. It is a milky white substance. This is highly soluble.

But if you pass excess carbon dioxide through the calcium hydroxide the reaction will form a mixture where you will find white solids suspended at the bottom of the container (or a u-tube if you are conducting the experiment in a lab).

This is the precipitate formed due to excess carbon dioxide and is known as calcium carbonate.

Learn More About precipitate with distilled water:

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Double displacement reaction example in which yellow precipitate is formed ​

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