Question

Which properties can be used to compute 2/5×[5×7/6]+1/3×(3×4/11)=?

Answer 1

$\huge{\textbf{A/Q\\\\\\BODMAS}}$

=2/5×[5×7/6]+1/3×(3×4/11)

=2/5×35/6+4/11

=7/3+4/11

=(77+12)/33

=89/33

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#Nishant

Answer 2

$\frac{2}{5} \times (5 \times \frac{7}{6} ) + \frac{1}{3} \times ( \frac{3}{4 \times 11} ) \\ = (\frac{2 \times 5 \times 7}{5 \times 6} ) + (\frac{1 \times 3}{3 \times 4 \times 11} ) \\ = \frac{7}{3} + \frac{1}{44} \\ = \frac{308 +3 }{132} \\ = \frac{311}{132}$