Question

Which quadratic equation is equivalent to (x – 4)2 – (x – 4) – 6 = 0?
(u – 4)2 – (u – 4) – 6 = 0 where u = (x – 4)
u2 – (u – 4) – 6 = 0 where u = (x – 4)
u2 – 16 – u – 6 = 0 where u = (x – 4)
u2 – u – 6 = 0 where u = (x – 4)

Answer 1

Answer:

Can not understand anything Pls ask again properly

Answer 2

Answer:

quad. equation = (x-4)2 - (x-4) - 6=0

2x-8-x+4-6=0

x-10=0

●for first = {(x-4)-4}2-{(x-4)-4}-6=0

(-4x+16)2-(-x+4-4)-6=0

-8x+32+x-6=0

-7x+26=0

first is not equal