Question

Which quantity is equivalent to 39 grams of LiF?

Answer 1

Answer:

1.5 moles of LiF is equivalent to 39 grams of LiF

Explanation:

the gram formula mass is the sum of the gram atomic masses of the atoms that make up a chemical formula. For lithium fluoride this works out to be 7g + 19g = 26g. Hence the mass of 1 mole of LiF is 26g; and the mass of 1.5 moles of LiF must be 1.5 × 26g = 39g

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