which s greater (1/2)^1/2 or(1/3)^1/3
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l÷sqrt 2 < l÷cuberoot3 as sqrt 2>cube root of 3
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wow, 5 answers lol idk why
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( 1/2 )^(1/2) > ( 1 / 3 )^( 1/3 )
Raise everything to the Power Six :
=> ( 1/2 )^3 > ( 1/3 )^2
=> ( 1 / 8 ) > ( 1 / 9 )
=> 9 > 8 which is obviously true and hence, our Assumption is true