Which sample at stp has the same number of atoms as 18 liters of Ne(g) at stp
Answers
Answered by
14
1- 5 grams of H2
2- 5 liters of CH4
3- 5 moles of O2
4- 5x10^23 molecules of CO2 (g)
Answered by
45
Welcome buddy,
Let's get our options right -
(1) 18 moles of Ar(g)
(2) 18 liters of Ar(g)
(3) 18 grams of H2O(g)
(4) 18 milliliters of H2O(g)
● Answer -
(2) 18 liters of Ar(g)
● Explanation -
- According to Avagadro's law, the amount (n) of a substance is directly proportional to the volume (V).
n1/v1 = n2/v2
- As no of atoms are same in both samples, n1 = n2.
n1/v1 = n1/v2
v1 = v2
- Hence, desired sample must be 18 litres volume which is option (2) here.
Hope this helps you...
Let's get our options right -
(1) 18 moles of Ar(g)
(2) 18 liters of Ar(g)
(3) 18 grams of H2O(g)
(4) 18 milliliters of H2O(g)
● Answer -
(2) 18 liters of Ar(g)
● Explanation -
- According to Avagadro's law, the amount (n) of a substance is directly proportional to the volume (V).
n1/v1 = n2/v2
- As no of atoms are same in both samples, n1 = n2.
n1/v1 = n1/v2
v1 = v2
- Hence, desired sample must be 18 litres volume which is option (2) here.
Hope this helps you...
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