Which scenario reflects an annual inflation rate of 3%? A. In year 1, the price of a computer is $325.00. In year 2, the same computer costs $328.00. B. In year 1, the price of a soda is $0.75. In year 2, the same soda costs $0.78. C. In year 1, the price of a board game is $10.00. In year 2, the same board game costs $10.03. D. In year 1, the price of a sofa is $500.00. In year 2, the same sofa costs $515.00.Which scenario reflects an annual inflation rate of 3%? A. In year 1, the price of a computer is $325.00. In year 2, the same computer costs $328.00. B. In year 1, the price of a soda is $0.75. In year 2, the same soda costs $0.78. C. In year 1, the price of a board game is $10.00. In year 2, the same board game costs $10.03. D. In year 1, the price of a sofa is $500.00. In year 2, the same sofa costs $515.00.
Answers
Answer:
First Case (Computer),
Price in year 1 = ₹325
Price in year 2 = ₹328
increased price = ₹328 - ₹325
= ₹ 3
Therefore, increased percentage = (3/325 × 100) ℅
= 300/325℅ (divide numerator & denominator both by 25)
= 12/13℅
Second Case (Soda),
Price in year 1 = ₹0.75
Price in year 2 = ₹0.78
increased price = ₹0.78- ₹0.75
= ₹ 0.03
Therefore, increased percentage = (0.03/0.75× 100) ℅
= (3/75 × 100)℅
= (1/25 × 100)℅
= 100/25 ℅ (divide numerator & denominator both by 25)
= 4℅
Third Case (Board game),
Price in year 1 = ₹10
Price in year 2 = ₹10.03
increased price = ₹10.03- ₹10
= ₹ 0.03
Therefore, increased percentage = (0.03/10 × 100) ℅
= 0.003 × 100℅
= 0.3℅
Forth Case (Sofa),
Price in year 1 = ₹500
Price in year 2 = ₹515
increased price = ₹515 - ₹500
= ₹ 15
Therefore, increased percentage = (15/500 × 100) ℅
= (3/100 × 100)℅
= 300/100℅
= 3℅
Answer :- Question no. D reflects an annuall inflation rate of 3℅