Question

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2? f(x) = –x2 – 8x – 16 f(x) = –x2 + 8x – 16 f(x) = –x2 – 8x + 16 f(x) = –x2 + 8x + 16

Answer 1

Answer:

f(x)=-x^2+8x-16

Step-by-step explanation:

For clarification, look this photo.