Which sequence of elements is arranged in the order of decreasing atomic radii?
(a) AI, SI, P
(b) Li, Na, K
(C) CI, Br, 1
(d) N, C, B
Answers
- atomic radius decreased from left to right in periodic table so option ( a) is correct .
The sequence of elements arranged in the order of decreasing atomic radii is Al, Si, P
Explanation for correct option:
• Therefore, the correct choice of the asked question is Option A.
• The correct sequence of order of decreasing atomic radii among all the options is:
Al > Si > P ,i.e.,
Aluminium > Silicon > Phosphorus
• Aluminium (Al), Silicon (Si) and Phosphorus (P) are present along a period and in a period, atomic radii decreases. So, Aluminium has higher atomic radii than Silicon and Phosphorus, and Phosphorus has the least atomic radii among Al, Si and P.
• The reason why atomic radii decreases along a group because while moving from left to right in a periodic table, Atomic number goes on increasing which means that number of protons and electrons increases.
In the same shell, extra electrons gets added along the period and hence due to large positive charge of the nucleus, the nucleus pulls the elctrons tightly and atomic radii gets decreased.
Explanation for incorrect options:
• Option (b) and (c) are incorrect because these elements belongs to the same group and in a group, the atomic radii of the elements increases.
• Option (d) is incorrect because while moving left to right in a periodic table, B (Boron) comes first, and then C (Carbon) and then N (Nitrogen). So, Boron (B) has larger Atomic radii and Nitrogen (N) has least atomic radii among N, C and B.
LEARN MORE:
How does the following vary in a period? Explain. (a) Atomic Size (b) Valence Electrons
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Explain variation of atomic size in the periodic table.
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