Question

Which set of conditions would you use to obtain the best yield in the reaction shown? 1-methyl-1-bromide-propane --?--> CH2=C-MeMe (a) Heat alone (b) H2O,heat (c) H2SO4 (d) Et O Na/EtOH, Heat ​

Answer 1

Answer:

if I should say means u should mark as BRAINLIEST and follow me

Answer 2

Answer:

t−butylMgBr gives butane as the major product and tertiary Grignard reagent is preferred. The product formed is butane. When Grignard reagent like alkylMgBr reacts with alkene we get alkane corresponding to the alkyl part of Grignard reagent. In this reagent, the C atom is more electronegative than Mg hence the alkyl part acts as a nucleophile and takes an active H to form the corresponding alkane and here butane.