Which set of numbers gives the correct possible values of l for n = 2? 0 0, 1 0, 1, 2 0, 1, 2, 3
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ans is 0,1 as 0 to l-1
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HEY THERE!!
For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1).
This means that the angular quantum number for a principal quantum number of 2 is equivalent to:
l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1
So the answer is 0,1
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