Which set of ordered pairs could be generated by an exponential function?
(-1, -1/2), (0, 0), (1, 1/2), (2, 1)
(–1, –1), (0, 0), (1, 1), (2, 8)
(-1, 1/2), (0, 1), (1, 2), (2, 4)
(–1, 1), (0, 0), (1, 1), (2, 4)
ANSWER ASAP PLEASE
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Answer:
f(x) = 2ˣ
(-1, 1/2), (0, 1), (1, 2), (2, 4)
Step-by-step explanation:
Let say
f(x) = bˣ
For x = 0
f(0) = b⁰ = 1
in given pairs only one pair having (0, 1)
Hence
(-1, 1/2), (0, 1), (1, 2), (2, 4) can be generated by an exponential function
Lets verify other values of it
f(-1) = b⁻¹ = 1/b = 1/2 => b = 2
f(0) = 2⁰ = 1
f(1) = 2¹ = 2
f(2) = 2² = 4
Hence f(x) = 2ˣ
(-1, 1/2), (0, 1), (1, 2), (2, 4) can be generated by an exponential function
Answered by
0
Answer:
Step-by-step explanation:
(-1, 1/2), (0, 1), (1, 2), (2, 4) is correct
Is the answer on Ed, Got 100% on my test
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