Question

Which set of ordered pairs could be generated by an exponential function?
(-1, -1/2), (0, 0), (1, 1/2), (2, 1)
(–1, –1), (0, 0), (1, 1), (2, 8)
(-1, 1/2), (0, 1), (1, 2), (2, 4)
(–1, 1), (0, 0), (1, 1), (2, 4)

ANSWER ASAP PLEASE

Answer 1

Answer:

f(x) = 2ˣ

(-1, 1/2), (0, 1), (1, 2), (2, 4)

Step-by-step explanation:

Let say

f(x) = bˣ

For x = 0

f(0) = b⁰ = 1

in given pairs only one pair having (0, 1)

Hence

(-1, 1/2), (0, 1), (1, 2), (2, 4)  can be generated by an exponential function

Lets verify other values of it

f(-1) = b⁻¹ = 1/b = 1/2  => b = 2  

f(0) = 2⁰ = 1

f(1) = 2¹ = 2

f(2) = 2² = 4

Hence f(x) = 2ˣ

(-1, 1/2), (0, 1), (1, 2), (2, 4)  can be generated by an exponential function

Answer 2

Answer:

Step-by-step explanation:

(-1, 1/2), (0, 1), (1, 2), (2, 4) is correct

Is the answer on Ed, Got 100% on my test