Question

Which set of quantum number is possible for the last electron of mg + ion?

Answer 1

Explanation:

The atomic number of magnesium is 12.

Therefore, the last filled orbital is the 3s orbital with two electrons pairing up.

Therefore, n = 3 (principal energy level for 3s) and l = 0 (for s orbital). For an electron, the spin is always 1/2.

Therefore,

n = 3, l = 0, s = 1/2 are the quantum numbers.

Answer 2

Answer:

The neutral magnesium element has shed one electron, making the magnesium ion (Mg+) a cation. As a result, the final electron of Mg+ will be in a distinct electrical state than the Mg atom in its neutral state.

Explanation:

The criteria for allocating quantum numbers must be followed in order to find the range of quantum numbers that are feasible for the final electron of the Mg+ ion:

• Any positive integer value beginning at one can be used for the primary quantum number (n).
• Any numerical value between 0 and n-1 can be used as the azimuthal quantum number (l).
• Any numerical value between -l and +l can be the magnetic quantum number (m).
• It is possible for the spin quantum number (s) to be +1/2 or -1/2.

Since it has taken an electron from the neutral magnesium element, the magnesium ion (Mg+) is a cation. The final electron of Mg+ will therefore be in a distinct electronic state than the Mg atom's neutral state. Following the guidelines for allocating quantum numbers, we can calculate the range of quantum numbers that the final electron of the Mg+ particle could have:

• The fundamental quantum number (n) can be any positive integer value beginning at 1.
• Azimuthal quantum number (l) can have any numerical value between 0 and n-1.
• From -l to +l, the magnetic quantum number (m) can have any integer value.
• Either +1/2 or -1/2 can be the spin quantum number (s).

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