Question

which set of quantum number values indicates maximum ionization energy of an electron present in particular orbit
a)n=2,l=1,m=0,s=+1/2
b)n=2,l=0,m=0,s=+1/2
c)n=3,l=2,m=0,s=+1/2
d)n=3,l=1,m=0,s=+1/2

Answer 1

Answer:

Two different values

The maximum value of the orbital angular momentum quantum number is one less than the principle quantum number. So maximum "l" value is 1 and it can take values from 0 to n-1. So possible values of "l" for n=2 is 0,1. Conclusion Two different values of l are possible for an electron with principal quantum number n=2.