Question

Which sets of side lengths represent Pythagorean triples? Check all that apply.
A. 1, 2, 5
B. 6, 8, 14
C. 8, 15, 17
D. 10, 24, 26
E. 15, 20, 30
F. 28, 45, 53

Answer 1

option C,D,F are phythagoran triplets

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Answer 2

Answer:

Step-by-step explanation:

Pythagoras theorem = $hypotenuse^{2} =perpendicular^{2} +base^{2}$

Now putting all the options we Will check Which sets of side lengths represent Pythagorean triples

A.  1, 2, 5

$5^{2} =2^{2} +1^{2}$

$25 =4 +1$

$25\neq 5$

Thus not a Pythagorean triples

B. 6, 8, 14

$14^{2} =6^{2} +8^{2}$

$196 =36 +64$

$196\neq 100$

Thus not a Pythagorean triples

C. 8, 15, 17

$17^{2} =15^{2} +8^{2}$

$289 =225 +64$

$289=289$

Thus a Pythagorean triples

D. 10, 24, 26

$26^{2} =10^{2} +24^{2}$

$676 =100 +576$

$676=676$

Thus a Pythagorean triples

E. 15, 20, 30

$30^{2} =15^{2} +20^{2}$

$900=225+400$

$900\neq 625$

Thus not a Pythagorean triples

F. 28, 45, 53

$53^{2} =28^{2} +45^{2}$

$2809=784+2025$

$2809=2809$

Thus a Pythagorean triples