Question

Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?

x2(4x + 1) – 2(4x + 1)
x2(4x – 1) + 2(4x – 1)
4x2(x + 2) – 1(x + 2)
4x2(x – 2) – 1(x – 2)

Answer 1

A.$x^2)4x+1)-2(4x+1)$

Step-by-step explanation:

Given:

$4x^3+x^2-8x-2$

Grouping the terms then we get

$(4x^3+x^2)+(-8x-2)$

Taking common 4x square from first bracket then, we get

$x^2(4x+1)+(-8x-2)$

Now,taking common-2 from second bracket then, we get

$x^2(4x+1)-2(4x+1)$

Hence, option A is true.

A.$x^2)4x+1)-2(4x+1)$

#Learn more:

https://brainly.com/question/1567135:Answered by Ckaranja

Answer 2

Answer:d

Step-by-step explanation: