Question

Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Quadratic formula:

Answer 1

Answer:

a = 3

b = -2

c = 0  

Step-by-step explanation:

Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula?

1 = –2x + 3x² + 1

=> 1 = 3x² - 2x + 1

Cancelling 1 from both sides

=> 0 = 3x² - 2x

interchanging LHS & RHS

=> 3x² - 2x = 0

comparing with

ax² + bx + c = 0

a = 3

b = -2

c = 0  

Answer 2

Answer:

a = -3, b = 2 and c = 0

Step-by-step explanation:

Since, the standard form of a quadratic equation is $ax^2+bx + c=0$,

Here, the given equation,

$1=-2x + 3x^2 + 1$

$1+2x -3x^2 - 1=0$

$-3x^2 + 2x = 0$

$-3x^2 + 2x + 0 = 0$

By comparing,

a = -3, b = 2 and c = 0