Which shows the equation below written in the form
ax^2 + bx + c = 0? x + 9 = 2(x - 1)2
A. 2x^2 - 3x - 7 = 0
B. 2x^2 - 5x + 11 = 0
C. 2x^2 - 3x + 11 = 0
D. 2x^2 - 5x - 7 = 0
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x + 9 = 2(x - 1)²
using identity (a - b)² = a² + b² - 2ab
x + 9 = 2(x² - 2x + 1)
x + 9 = 2x² - 4x + 2
2x² - 4x - x + 2 - 9 = 0
2x² - 5x - 7 = 0 Answer
hope this helps you
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