Question

which smallest 3 digit number is divisible by 12, 18 and 24​

Answer 1

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Lowest Common Factor

12 = 2x2x2

18 = 2x2x3

24 = 2x2x2x3

LCM = 2x2x2x3

= 24

So, 24 x 5 = 120

Therefore, 120 is your answer.

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Answer 2

SOLUTION

TO DETERMINE

The smallest 3 digit number divisible by 12 , 18 and 24

EVALUATION

Here the given numbers are 12 , 18 and 24

Now we find the LCM of the numbers

12 = 2 × 2 × 3

18 = 2 × 3 × 3

24 = 2 × 2 × 2 × 3

LCM = 2 × 2 × 2 × 3 × 3 = 72

Now

72 × 1 = 72

72 × 2 = 144

Hence the required smallest 3 digit number divisible by 12 , 18 and 24 is 144

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