Which smallest number should be added to 2600, so it gets divided by 9? answer if you know spam will be reported.... please....
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We have to find the number which when added to 2600 makes it divisible by 9.
Divisibility test of 9 - If Sum of numbers is divisible by 9 then the number is also divisible by 9.
Let the number divisible be x
So,
2 + 6 + 0 + 0 + x must be equal to the number divisible by 9.
Sum of these numbers = 8
Number closest to 8 and divisible be 9 is 9.
So, x + 8 = 9
x = 9 - 8
x = 1
Smallest number divisible that must be added to 2600 to make it divisible by 9 is 1.
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