which smallest number should be added to the difference of squres of 53 and 47 so that it become a prefect square?
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Answered by
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53^2 - 47^2 = (53+47)(53-47) = 100(6) = 600
As 24^2 = 576 and 25^2 = 625
So 625 -600 = 25 should be added
As 24^2 = 576 and 25^2 = 625
So 625 -600 = 25 should be added
adityahansda10:
thanks
Answered by
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the smallest number is 6
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i hope it help you
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not right answer
53^2 - 47^2=(53+4)(53-47)=100(6)=600 as 24^2=576 and 25^2=625 so 625-600=25 should be added
answer is=25
thanks all of you
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