Math, asked by engislam088, 3 months ago

Which smallest number will have 5 as remainder in every case when divided with 8,12,18,24

Answers

Answered by pousalidolai59

8

Answer:

Solution: Factors of

8 = 2x2x2

12 = 2x2x3

18 = 2x3x3

24 = 2x2x2x3

LCM = 2x2x2x3x3 = 72

Add 5 to 72 to get 77 as the answer.

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