Question

Which solution has same elevation of boiling point as 0.1m NaCl

Answer 1

The elevation in boiling point is calculated as  

△T  

b

​  

=i×K  

b

​  

×m

i is the Vant Hoff Factor.

K  

b

​  

 is the molal elevation constant

m is molality

For NaCl, the Vant Hoff Factor comes out to be two as it is an ionic compound while for glucose Vant Hoff Factor is 1 as it cannot dissociate in the solution. Therefore, elevation in boiling point would not be same.