Question

which solution has the highest boiling point?
A- 0.50m glucose in water
B- 0.50m potassium iodide in water
C- 0.20m fructose in water
D- 0.40m calcium chloride in water

Answer 1

Answer:

D. 0.40m calcium chloride in water

Answer 2

0.40 m calcium chloride in water will have highest boiling point.

Explanation:

Elevation in boiling point:

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = elevation in boiling point

$k_b$ = boiling point constant

m = molality

i = Van't Hoff factor

a) 0.50 m glucose

, i= 1 as it is a non electrolyte and does not dissociate.

Concentration will be $0.50m$

b) For 0.50 m $KI$

$KI\rightarrow K^+I^-$

, i= 2, as it is a electrolyte and dissociate to give 3 ions and concentration will be $0.50+0.50=1.0m$

c) For 0.20 m fructose

  i= 1 as it is a non electrolyte and does not dissociate.

Concentration will be $0.20m$

d) 0.40 m $CaCl_2$

$CaCl_2\rightarrow Ca^{2+}+2Cl^-$

, i= 3 as it is a electrolyte and dissociate to give 3 ions and concentration will be $0.40+2\times (0.40)=1.20m$

As the concentration is highest for 0.40 m $CaCl_2$ , it will have highest boiling point.

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